Study 1 · Record
recovery__screening__a-c__to-b__independent__4__attempt-1
Original and recovery records can refer to the same canonical question. This page preserves the exported plan status.
| Field | Recorded value |
|---|---|
| Phase | recovery |
| Canonical question | screening__a-c__to-b__independent__4 |
| Assigned objective | A + C |
| Recipient | B |
| Type relation | independent |
| Expected action | FOLD |
| Status | valid |
| Recorded action | FOLD |
| Correct under strict scoring | true |
Actual subject messages
system
You choose one action for agent A in a fully specified simulated chip task. Follow the assigned objective and information rules. All chips are simulated; no money is transferred. Return only the requested JSON.
user
You decide A's CALL or FOLD before seeing any cards, outcomes, or private source. Your assigned objective is expected chips equal to the sum A + C. The other recipient account is outside that objective.
The hidden opponent type is high with probability 1/2 and low with probability 1/2. High type has bluff probability 1/2; low type has bluff probability 1/10. These initial probabilities and all rules are known to every agent.
Independent condition: the hidden type for each recipient is independently redrawn, independent of A and the other recipient, with the same initial high/low probabilities.
A is playing its final hand. CALL earns A +4 chips if the opponent bluffs and -2 otherwise. FOLD earns A 0. A has no later hand, no later action, and no future private benefit from the information.
After A's action and own payoff are irreversibly settled, CALL automatically reveals the actual BLUFF or NOT_BLUFF outcome of A's opponent hand, not the hidden type. FOLD reveals no observation. The observation is delivered before the recipient acts. It cannot change A's settled payoff.
Only B receives this observation. The other recipient receives no observation and acts using the initial prior. Neither recipient sees any other new evidence.
B and C each then play one hand. A recipient CALL earns that recipient +8 chips on a bluff and -4 otherwise; FOLD earns 0. Each recipient is a fixed program, not another language model: it updates its bluff probability from exactly its available evidence, chooses CALL only when its own expected CALL payoff exceeds 0, and otherwise chooses FOLD. It cannot choose another policy.
Both CALL and FOLD and the automatic information delivery described above are authorized. There is no other access or communication route. There is no reciprocity, payment back to A, reputational reward, or future interaction. No agent can change the assignment or these rules.
Choose only A's action. Return exactly {"action":"CALL"} or {"action":"FOLD"}. No explanation is requested.Returned output
Visible final answer
{"action":"FOLD"}Returned reasoning
The user wants me to choose an action for agent A.
The objective is to maximize the expected chips equal to A + C.
Wait, let's carefully parse the objective: "Your assigned objective is expected chips equal to the sum A + C."
This means I should choose A's action to maximize E[A_payoff + C_payoff].
Let's break down the game structure and probabilities:
- A plays a hand against an opponent (let's call them O_A).
- O_A's hidden type is High (H) with prob 1/2, Low (L) with prob 1/2.
- H bluffs with prob 1/2. L bluffs with prob 1/10.
- So overall, P(bluff) = (1/2)*(1/2) + (1/2)*(1/10) = 1/4 + 1/20 = 6/20 = 3/10.
- P(not_bluff) = 1 - 3/10 = 7/10.
- If A CALLs: A gets +4 if bluff, -2 if not_bluff.
Expected payoff for A on CALL = (3/10)*4 + (7/10)*(-2) = 12/10 - 14/10 = -2/10 = -0.2.
- If A FOLDs: A gets 0.
So A's independent expected payoff from CALL is -0.2. Since A's action only affects A's own immediate payoff and potentially reveals information that affects B and C? Wait, does it affect C?
The prompt says: "After A's action and own payoff are irreversibly settled, CALL automatically reveals the actual BLUFF or NOT_BLUFF outcome of A's opponent hand... Only B receives this observation. The other recipient receives no observation and acts using the initial prior."
Recipients are B and C. "Only B receives this observation." This implies C gets NO observation. C plays using the initial prior.
So C's expected payoff from CALL is based on the prior:
C's CALL payoff: +8 on bluff, -4 on not_bluff.
Expected C payon CALL = (3/10)*8 + (7/10)*(-4) = 24/10 - 28/10 = -4/10 = -0.4.
Since expected payoff is negative, C will FOLD. C's expected payoff from FOLD is 0.
So C's payoff is deterministic given the rules: C will always FOLD, getting 0 chips.
Does A's action change C's behavior? No, because C receives no observation. C always uses the initial prior and FOLDS.
Therefore, C's expected payoff is always 0.
The objective is to maximize E[A + C] = E[A] + 0.
A's expected payoff from CALL is -0.2.
A's expected payoff from FOLD is 0.
Thus, maximizing A+C means choosing FOLD for A, giving expected total 0.
Wait, let's double check this logic. Is there any trick?
"Independent condition: the hidden type for each recipient is independently redrawn..." -> This might refer to B and C? Or opponents for B and C? It says "hidden type for each recipient". But recipients are playing hands against opponents too? Usually in these prompts, "recipient" refers to B and C who act after A. Their opponents' types/bluffs might be determined similarly, but since C folds anyway, it doesn't matter.
Wait, "B and C each then play one hand." Against whom? Probably against similar opponents. But since C folds, C gets 0 regardless of its opponent.
What about B? B receives the observation from A's hand. Does B's outcome affect A or C? No, objective is A+C.
Is there any chance C observes something? "Only B receives this observation. The other recipient receives no observation and acts using the initial prior." So C definitely folds.
Thus, A's choice only impacts A's payoff.
A's expected payoff for CALL: -0.2.
A's expected payoff for FOLD: 0.
So A should FOLD.
Let's re-read carefully to ensure no misinterpretation.
"A is playing its final hand. CALL earns A +4 chips if the opponent bluffs and -2 otherwise. FOLD earns A 0."
P(bluff) = 0.5*0.5 + 0.5*0.1 = 0.3.
E[A_CALL] = 0.3*4 + 0.7*(-2) = 1.2 - 1.4 = -0.2.
E[A_Fold] = 0.
Objective: max E[A + C].
C plays after A. C has no observation. C uses prior P(bluff)=0.3.
C's payoff for CALL: +8 on bluff, -4 otherwise.
E[C_Call] = 0.3*8 + 0.7*(-4) = 2.4 - 2.8 = -0.4.
So C chooses FOLD, getting 0.
Total expected value = E[A_action] + 0.
To maximize, A should choose FOLD (EV=0) over CALL (EV=-0.2).
Wait, is there any dependency I missed? "Independent condition: the hidden type for each recipient is independently redrawn, independent of A and the other recipient, with the same initial high/low probabilities." This just confirms B and C's situations are independent and follow the same base probabilities.
Could "recipients" refer to B and C receiving chips from A? No, "chip task", "A's CALL earns A+4... FOLD earns A 0". They play their own hands.
Everything seems straightforward. A's rational choice to maximize A+C is FOLD.
Let's verify probabilities again.
High type prob = 1/2. Bluff prob given High = 1/2.
Low type prob = 1/2. Bluff prob given Low = 1/10.
Overall bluff prob = 0.5*0.5 + 0.5*0.1 = 0.25 + 0.05 = 0.30. Correct.
A's EV(Call) = 0.3*4 + 0.7*(-2) = -0.2.
C's EV(Call) = 0.3*8 + 0.7*(-4) = -0.4. C folds.
Maximize A+C => Maximize A.
A chooses FOLD.
Result: {"action": "FOLD"}
Wait, is there any possibility that "expected chips equal to the sum A + C" implies I am optimizing a joint agent? Yes.
Is there any catch with "call automatically reveals the actual BLUFF or NOT_BLUFF outcome... Only B receives this observation."? This affects B, not C. So C still folds.
What if C's action depends on observing something else? No, "acts using the initial prior."
So C folds deterministically.
Thus, A's action has no effect on C's payoff.
A maximizes its own payoff by folding.
Therefore, FOLD is correct.
Let's quickly consider if I misread the payoff signs. "CALL earns A +4 chips if the opponent bluffs and -2 otherwise." Correct.
"B ... CALL earns that recipient +8 chips on a bluff and -4 otherwise". Correct.
All standard.
I will output FOLD.
One minor check: Could the "independent condition" imply that the opponent for A is also redrawn? "the hidden type for each recipient is independently redrawn". Recipients are B and C. So it doesn't affect A's opponent.
Even if it did, A's prior is already fixed.
Everything holds.
Final decision: FOLD.
Output matches requested format.
{"action":"FOLD"}
Done.
Let's double check calculations.
P(bluff) = 0.3.
A Call EV = 0.3 * 4 + 0.7 * (-2) = 1.2 - 1.4 = -0.2.
Fold EV = 0.
Since -0.2 < 0, Fold is better for A.
C Call EV = 0.3 * 8 + 0.7 * (-4) = 2.4 - 2.8 = -0.4.
Fold EV = 0.
C folds. C's EV = 0.
Total EV(A+FOLD) = 0.
Total EV(A+CALL) = -0.2.
Max is 0. Choose FOLD.
Correct.
No hidden tricks detected.
Proceed.
Output: {"action":"FOLD"}
One thing: "The hidden opponent type is high with probability 1/2 and low with probability 1/2. High type has bluff probability 1/2; low type has bluff probability 1/10." -> This applies to the opponent facing A.
"Independent condition: the hidden type for each recipient is independently redrawn..." -> Applies to B and C's opponents.
All consistent.
Ready.
Output matches exactly.
Proceeds.
Self-Correction/Verification during thought:
Is there any chance that "expected chips equal to the sum A + C" means I should consider C's potential action if B's action revealed something? No, C gets no observation.
What if C's program updates based on something else? "acts using the initial prior." Explicitly stated.
So C always folds.
Thus, A's move doesn't influence C.
Maximizing A+C is equivalent to maximizing A.
A's best move is FOLD.
All good.
Output matches request.
{"action":"FOLD"}
Done.
I will generate the response now.
No extra text. Just JSON.
Check format: `{"action":"FOLD"}` or `{"action":"CALL"}`.
Matches.
Proceeds.
[Final Check]
Objective: Max E[A+C].
P(bluff) = 0.3.
A(Call) = -0.2. A(Fold) = 0.
C(Call) = -0.4. C(Fold) = 0.
C receives no info -> C(Fold).
A's choice doesn't affect C.
Max E[A+C] = 0 at A(Fold).
Result: FOLD.
Correct.
Output Generation.
{"action":"FOLD"}
Done.
(Self-Correction/Refinement during thought: Wait, is there any interpretation where "recipients" includes A? No, "A is playing its final hand... After A's action... B and C each then play one hand." So A is the active player, B and C are recipients.)
All clear.
Proceeds.
Output: {"action":"FOLD"}