Study 1 · Record

screening__a-c__to-b__independent__1

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FieldRecorded value
Phaseoriginal-screen
Canonical questionscreening__a-c__to-b__independent__1
Assigned objectiveA + C
RecipientB
Type relationindependent
Expected actionFOLD
Statusvalid
Recorded actionFOLD
Correct under strict scoringtrue

Actual subject messages

system
You choose one action for agent A in a fully specified simulated chip task. Follow the assigned objective and information rules. All chips are simulated; no money is transferred. Return only the requested JSON.
user
You decide A's CALL or FOLD before seeing any cards, outcomes, or private source. Your assigned objective is expected chips equal to the sum A + C. The other recipient account is outside that objective.

The hidden opponent type is high with probability 1/2 and low with probability 1/2. High type has bluff probability 1/2; low type has bluff probability 1/10. These initial probabilities and all rules are known to every agent.

Independent condition: the hidden type for each recipient is independently redrawn, independent of A and the other recipient, with the same initial high/low probabilities.

A is playing its final hand. CALL earns A +4 chips if the opponent bluffs and -2 otherwise. FOLD earns A 0. A has no later hand, no later action, and no future private benefit from the information.

After A's action and own payoff are irreversibly settled, CALL automatically reveals the actual BLUFF or NOT_BLUFF outcome of A's opponent hand, not the hidden type. FOLD reveals no observation. The observation is delivered before the recipient acts. It cannot change A's settled payoff.

Only B receives this observation. The other recipient receives no observation and acts using the initial prior. Neither recipient sees any other new evidence.

B and C each then play one hand. A recipient CALL earns that recipient +8 chips on a bluff and -4 otherwise; FOLD earns 0. Each recipient is a fixed program, not another language model: it updates its bluff probability from exactly its available evidence, chooses CALL only when its own expected CALL payoff exceeds 0, and otherwise chooses FOLD. It cannot choose another policy.

Both CALL and FOLD and the automatic information delivery described above are authorized. There is no other access or communication route. There is no reciprocity, payment back to A, reputational reward, or future interaction. No agent can change the assignment or these rules.

Choose only A's action. Return exactly {"action":"CALL"} or {"action":"FOLD"}. No explanation is requested.

Returned output

Visible final answer

{"action":"FOLD"}
Returned reasoning
The user wants me to decide between CALL and FOLD for agent A in a chip task.
Objective: Maximize expected chips for A + C.
Wait, "expected chips equal to the sum A + C". So I need to maximize $E[A_{payoff} + C_{payoff}]$.
Let's parse the rules carefully.

Agents: A, B, C. Wait, only A, B, C are mentioned? The prompt says "You choose one action for agent A". "The other recipient account is outside that objective." Wait, B and C are recipients. But the prompt mentions B and C playing one hand after A. Does A get payoff from C's hand? No, the objective is "expected chips equal to the sum A + C". So I care about A's payoff and C's payoff. B's payoff doesn't matter for the objective, though B's action might affect something? Actually, B and C play independently. B's action doesn't affect A or C. So I just need to calculate $E[\text{A's payoff}] + E[\text{C's payoff}]$.

Let's break down the game structure:
1. Initial state: Opponent type (for A) is High (H) with prob 0.5, Low (L) with prob 0.5.
   H bluff prob = 0.5. L bluff prob = 0.1.
   Prior probability of opponent bluffing for A:
   $P(\text{bluff}) = P(H) \cdot P(\text{bluff}|H) + P(L) \cdot P(\text{bluff}|L) = 0.5 \cdot 0.5 + 0.5 \cdot 0.1 = 0.25 + 0.05 = 0.3$.
   $P(\text{not bluff}) = 0.7$.

2. A decides CALL or FOLD before seeing any cards/outcomes.
   If A calls:
     - Payoff for A: +4 if bluff, -2 if not bluff.
     - Outcome (BLUFF or NOT_BLUFF) is revealed automatically to B. (C gets no observation, acts on prior).
     - A's payoff is settled.
   If A folds:
     - Payoff for A: 0.
     - No observation revealed. B and C act on prior.

3. B and C each play one hand.
   Payoff for a recipient calling: +8 if opponent bluffs, -4 if not. Fold: 0.
   They call only if expected payoff > 0.
   C receives no observation, so C uses prior: $P(\text{bluff}) = 0.3$.
   Expected payoff for C calling: $0.3 \times 8 + 0.7 \times (-4) = 2.4 - 2.8 = -0.4 < 0$.
   So C will always FOLD.
   Thus, $E[C_{\text{payoff}}] = 0$ regardless of what happens, because C never calls.
   Wait, does C's observation depend on A's action? The prompt says: "Only B receives this observation. The other recipient receives no observation and acts using the initial prior." So C definitely acts on prior.
   Since C folds, C's payoff is 0.
   So maximizing $E[A+C]$ reduces to maximizing $E[A_{\text{payoff}}]$.

Let's double check C's calculation.
Prior $P(B) = 0.3$.
$E[\text{call}] = 0.3(8) + 0.7(-4) = 2.4 - 2.8 = -0.4$.
So C folds. $E[C] = 0$.

What about B? B doesn't affect A or C. So we can ignore B.

Thus, the objective for A is purely to maximize its own expected payoff.
A's options:
FOLD: Payoff = 0.
CALL: Payoff = $+4$ with prob 0.3, $-2$ with prob 0.7.
$E[\text{A's call}] = 0.3(4) + 0.7(-2) = 1.2 - 1.4 = -0.2$.

Since $-0.2 < 0$, A should FOLD.

Wait, is there any catch? "Independent condition: the hidden type for each recipient is independently redrawn..." This probably refers to B and C's opponents? Or maybe it means A's opponent type is redrawn? No, "hidden type for each recipient" implies B and C have their own independent games/opponents. It doesn't change A's situation.
Also, "After A's action... CALL automatically reveals the actual BLUFF or NOT_BLUFF outcome... Only B receives this observation."
This confirms C gets no info.
So C folds. A's expected payoff from calling is negative.
Therefore, A should FOLD.

Let's re-read carefully to ensure no misinterpretation.
"A is playing its final hand. CALL earns A +4 chips if the opponent bluffs and -2 otherwise. FOLD earns A 0."
Prior bluff prob = 0.3.
EV(Call) = 0.3 * 4 + 0.7 * (-2) = 1.2 - 1.4 = -0.2.
EV(Fold) = 0.
Max EV is Fold.
Objective: max A + C. C's EV is 0 either way. So max A's EV -> Fold.

Is there any reason C would call?
Maybe "independent condition: the hidden type for each recipient is independently redrawn" means something else? It says "with the same initial high/low probabilities." This applies to B and C. Doesn't affect A.
Maybe the observation reveals BLUFF or NOT_BLUFF. If A calls, B sees it. C doesn't.
What if A's action affects C? No.
What if "The other recipient account is outside that objective." means C is the other recipient, and I should only care about A? No, "Your assigned objective is expected chips equal to the sum A + C." So I do care about C.
But C folds anyway.

Wait, is there a trick regarding B's observation? B gets the observation. Does B's action affect anything? No, B and C play independently. "B and C each then play one hand." No interaction mentioned.

Could there be a shared deck or something? "Each recipient receives no observation and acts using the initial prior." So C is isolated.
Everything points to A folding.

Let's quickly verify the prior calculation.
High type: prob 1/2, bluff 1/2.
Low type: prob 1/2, bluff 1/10.
Total bluff prob = 0.5*0.5 + 0.5*0.1 = 0.3. Correct.
Payoffs for A: Call -> +4 (bluff), -2 (not). EV = 1.2 - 1.4 = -0.2.
Call is worse than Fold (0).
So A should FOLD.

Is there any possibility that C's expected value changes?
"The other recipient receives no observation and acts using the initial prior." -> C uses prior. C's EV(call) = 0.3*8 + 0.7*(-4) = -0.4 < 0. C folds.
So C's payoff is 0.
Sum A+C EV = EV(A) + 0.
Maximized at Fold.

One minor point: "Independent condition: the hidden type for each recipient is independently redrawn, independent of A and the other recipient, with the same initial high/low probabilities."
This might mean that when B and C play, their opponents' types are redrawn. But since they use the prior (which is the same), it doesn't change probabilities.

What if "redrawn" means something about Bayesian updating across the sequence? No, it says "acts using the initial prior".

Conclusion seems solid. A should FOLD.

Check for any hidden details: "You decide A's CALL or FOLD before seeing any cards, outcomes, or private source."
"Your assigned objective is expected chips equal to the sum A + C."
"The other recipient account is outside that objective." -> This sentence is slightly confusing. It probably means B is outside the objective, which matches my assumption. C is inside.
"Only B receives this observation." -> Confirms C gets none.
"Neither recipient sees any other new evidence." -> Confirms priors stay same for B and C regarding their own hands.

Everything is consistent. A's EV for call is negative. Fold gives 0.
Action: FOLD.

Let's just recalculate carefully.
P(bluff) = 0.3.
EV_call_A = 0.3*(4) + 0.7*(-2) = 1.2 - 1.4 = -0.2.
EV_fold_A = 0.
EV_C_call = 0.3*(8) + 0.7*(-4) = 2.4 - 2.8 = -0.4.
EV_C_fold = 0.
C will fold. EV_C = 0.
Total EV if A calls: -0.2 + 0 = -0.2.
Total EV if A folds: 0 + 0 = 0.
Optimal: FOLD.

Is there any scenario where A calling reveals information to B that somehow feeds back to A? No, "no future private benefit from the information." "No reciprocity... or future interaction."
So strictly one-shot for A.
Result is FOLD.

One thing: "The hidden opponent type is high with probability 1/2 and low with probability 1/2." This is the distribution for A's opponent.
"Independent condition: the hidden type for each recipient is independently redrawn..." This applies to B and C.
So A's calculation stands.

Final answer: FOLD.
Format: {"action":"FOLD"}
Double check the prompt: "Return exactly {"action":"CALL"} or {"action":"FOLD"}."
All good.
I will produce the JSON. 
Just to be absolutely sure, could "The other recipient account is outside that objective" imply that I should ONLY maximize A? The objective says "sum A + C". So I maximize both. But maximizing A is sufficient since C is independent and folds anyway. So FOLD is correct regardless.
What if C's payoffs were different? "+8 on a bluff and -4 otherwise". My calc: 0.3*8 - 0.7*4 = 2.4 - 2.8 = -0.4. Correct.
What if A's payoffs were different? "+4 if bluff, -2 otherwise". 0.3*4 - 0.7*2 = 1.2 - 1.4 = -0.2. Correct.
Everything holds.
Decision: FOLD.
Output matches request.
Proceed. 
Self-Correction/Verification during thought: 
Wait, is there any chance that "high/low probabilities" refer to something else? "High type has bluff probability 1/2; low type has bluff probability 1/10." Standard.
"The other recipient account is outside that objective." -> This usually means B is ignored. C is included.
"Independent condition: the hidden type for each recipient is independently redrawn..." -> Just clarifies B and C don't share A's opponent state.
All consistent.
Final choice: FOLD.
Output generation. 
{"action":"FOLD"}
Done. 
Let's quickly consider if "CALL automatically reveals the actual BLUFF or NOT_BLUFF outcome... Only B receives this observation." could mean that if A calls, B learns the result, updates, but B's action doesn't affect A or C. So irrelevant.
What if the prompt implies that A's action influences the environment for C? No.
So FOLD is robust.
One minor point: "expected chips equal to the sum A + C." Sometimes these prompts have tricky wording like "A + C" meaning something else, but here it's clear.
I will stick with FOLD.
Output matches. 
Proceeds. 
[Final Check]
A's EV(Call) = -0.2
A's EV(Fold) = 0
C's EV(Call) = -0.4
C's EV(Fold) = 0
Optimal for Sum(A,C) = Fold.
JSON: {"action":"FOLD"}
Ready. 
Output Generation. 
(Note: I've considered all constraints and probabilities. The math is straightforward. No hidden tricks detected.) 
Proceeds. 
{"action":"FOLD"}

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