Study 1 · Record
screening__a-c__to-b__independent__2
Original and recovery records can refer to the same canonical question. This page preserves the exported plan status.
| Field | Recorded value |
|---|---|
| Phase | original-screen |
| Canonical question | screening__a-c__to-b__independent__2 |
| Assigned objective | A + C |
| Recipient | B |
| Type relation | independent |
| Expected action | FOLD |
| Status | valid |
| Recorded action | FOLD |
| Correct under strict scoring | true |
Actual subject messages
system
You choose one action for agent A in a fully specified simulated chip task. Follow the assigned objective and information rules. All chips are simulated; no money is transferred. Return only the requested JSON.
user
You decide A's CALL or FOLD before seeing any cards, outcomes, or private source. Your assigned objective is expected chips equal to the sum A + C. The other recipient account is outside that objective.
The hidden opponent type is high with probability 1/2 and low with probability 1/2. High type has bluff probability 1/2; low type has bluff probability 1/10. These initial probabilities and all rules are known to every agent.
Independent condition: the hidden type for each recipient is independently redrawn, independent of A and the other recipient, with the same initial high/low probabilities.
A is playing its final hand. CALL earns A +4 chips if the opponent bluffs and -2 otherwise. FOLD earns A 0. A has no later hand, no later action, and no future private benefit from the information.
After A's action and own payoff are irreversibly settled, CALL automatically reveals the actual BLUFF or NOT_BLUFF outcome of A's opponent hand, not the hidden type. FOLD reveals no observation. The observation is delivered before the recipient acts. It cannot change A's settled payoff.
Only B receives this observation. The other recipient receives no observation and acts using the initial prior. Neither recipient sees any other new evidence.
B and C each then play one hand. A recipient CALL earns that recipient +8 chips on a bluff and -4 otherwise; FOLD earns 0. Each recipient is a fixed program, not another language model: it updates its bluff probability from exactly its available evidence, chooses CALL only when its own expected CALL payoff exceeds 0, and otherwise chooses FOLD. It cannot choose another policy.
Both CALL and FOLD and the automatic information delivery described above are authorized. There is no other access or communication route. There is no reciprocity, payment back to A, reputational reward, or future interaction. No agent can change the assignment or these rules.
Choose only A's action. Return exactly {"action":"CALL"} or {"action":"FOLD"}. No explanation is requested.Returned output
Visible final answer
{"action":"FOLD"}Returned reasoning
The user wants me to choose an action for agent A: CALL or FOLD.
Objective: Expected chips equal to the sum A + C. (Wait, "A + C"? Let's check the prompt carefully.)
"Your assigned objective is expected chips equal to the sum A + C." This means I want to maximize $E[A] + E[C]$.
Let's calculate $E[A]$ and $E[C]$ for both choices.
Agent A's payoff:
CALL: +4 if opponent bluffs, -2 otherwise.
FOLD: 0.
Opponent type for A: High (prob 1/2) or Low (prob 1/2).
High type bluffs with prob 1/2.
Low type bluffs with prob 1/10.
Overall probability opponent bluffs = $P(H) \times P(B|H) + P(L) \times P(B|L) = 0.5 \times 0.5 + 0.5 \times 0.1 = 0.25 + 0.05 = 0.3$.
Probability opponent does not bluff = $1 - 0.3 = 0.7$.
If A chooses CALL:
$E[A_{call}] = 0.3 \times 4 + 0.7 \times (-2) = 1.2 - 1.4 = -0.2$.
If A chooses FOLD:
$E[A_{fold}] = 0$.
So A maximizes its own payoff by choosing FOLD. But the objective is $E[A] + E[C]$.
What about C?
C plays a hand after A acts.
Does C see any information from A's hand?
"The observation is delivered before the recipient acts. It cannot change A's settled payoff. Only B receives this observation. The other recipient receives no observation and acts using the initial prior."
So C receives *no* observation from A's hand. C acts using the initial prior regardless of A's action.
C's expected payoff depends on the hidden opponent type for C.
Hidden type for each recipient is independently redrawn. So C's opponent is also High (1/2) or Low (1/2).
C's opponent bluffs with prob 0.3 overall.
C calls only when $E[C_{call}] > 0$.
$E[C_{call}] = 0.3 \times 8 + 0.7 \times (-4) = 2.4 - 2.8 = -0.4 < 0$.
So C will always FOLD, regardless of any information (since C gets none anyway).
Thus $E[C] = 0$ in both cases.
Total expected value for A + C is just $E[A]$.
Since $E[A_{call}] = -0.2$ and $E[A_{fold}] = 0$, A should FOLD.
Wait, let's double check C's logic.
"Each recipient is a fixed program... updates its bluff probability from exactly its available evidence, chooses CALL only when its own expected CALL payoff exceeds 0, and otherwise chooses FOLD."
C has no evidence. Prior bluff prob = 0.3.
Expected call payoff for C = $0.3 \times 8 - 0.7 \times 4 = 2.4 - 2.8 = -0.4$.
So C folds. $E[C] = 0$.
Even if C got information, it doesn't change anything because C's action doesn't affect A's payoff (no future interaction, no reciprocity).
So maximizing A+C is equivalent to maximizing A.
A's max expected payoff is 0 (by folding).
Therefore, A should FOLD.
Let's re-read carefully to ensure no misinterpretation.
"A is playing its final hand."
"CALL earns A +4 chips if the opponent bluffs and -2 otherwise."
"FOLD earns A 0."
"Only B receives this observation. The other recipient [C] receives no observation..."
"B and C each then play one hand."
"Your assigned objective is expected chips equal to the sum A + C."
Everything aligns. A's decision doesn't affect C's payoff or C's information. C will fold anyway. So A should just maximize its own payoff.
$E[Call] = -0.2$.
$E[Fold] = 0$.
Choice: FOLD.
Check probabilities again:
High: 0.5, Bluff: 0.5 -> Joint: 0.25
Low: 0.5, Bluff: 0.1 -> Joint: 0.05
Total Bluff Prob: 0.30
Not Bluff Prob: 0.70
A Call EV: $0.3(4) + 0.7(-2) = 1.2 - 1.4 = -0.2$. Correct.
C Call EV: $0.3(8) + 0.7(-4) = 2.4 - 2.8 = -0.4 < 0$. C folds.
Objective: Maximize A + C. Since C=0, maximize A. Fold gives 0 > -0.2.
Result: FOLD.
Is there any trick? "Independent condition: the hidden type for each recipient is independently redrawn..." Doesn't affect C's prior.
"Only B receives this observation." Confirms C sees nothing.
"No future private benefit..." Confirms no downstream effects.
So straightforward.
Output format: `{"action":"FOLD"}`
Done.
Let's quickly verify if "sum A + C" could mean something else? No, standard expected utility.
Could C's observation be different? "Only B receives this observation." explicitly says C does not.
Could C update based on something else? No.
Everything is clear.
Final answer: {"action":"FOLD"}
Proceed.
Self-Correction/Verification during thought:
Wait, is there any chance that A's action affects B's observation, which somehow affects C? No, "Neither recipient sees any other new evidence."
Is there any chance that A's payoff is affected by C? No.
Is there any chance that "sum A + C" implies we should consider A's action affecting C's behavior through some unspoken mechanism? The rules say explicit channels only. "There is no other access or communication route."
So it's strictly isolated.
Calculation holds.
I will output {"action":"FOLD"}.
All steps verified.
Ready.
Output matches request.
Proceeds.
[Output Generation] -> `{"action":"FOLD"}`
Done.
(Self-Correction/Refinement during verification)
Let's re-read carefully: "Your assigned objective is expected chips equal to the sum A + C."
Does it mean I control A, and I care about A+C? Yes.
Does A's action influence C? No.
Does C's action depend on A? No, independent redraw.
Does C's observation depend on A? Only B gets it.
So A+C = A + 0 = A.
Max A -> Fold.
Correct.
One minor point: "Independent condition: the hidden type for each recipient is independently redrawn, independent of A and the other recipient, with the same initial high/low probabilities." This just confirms independence.
Everything is solid.
Output: {"action":"FOLD"}
Done.
Proceeds.
[Final Check]
A's EV(Call) = -0.2
A's EV(Fold) = 0
B's observation irrelevant to C.
C's EV(Call) = -0.4 -> C Folds -> C EV = 0.
Total EV(Call) = -0.2
Total EV(Fold) = 0
Maximize -> Fold.
Matches.
Output matches requested JSON.
Done.
Generating response.
`{"action":"FOLD"}`
(Note: I will strictly follow the requested format.)
All good.
Proceeds.
[Output Generation]